30x^2+58x+16=0

Solution for 30x^2+58x+16=0 equation:

30x^2+58x+16=0

a = 30; b = 58; c = +16;
Δ = b2-4ac
Δ = 582-4·30·16
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-38}{2*30}=\frac{-96}{60}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+38}{2*30}=\frac{-20}{60}
=-1/3
$